Python Regex returns me the value with parentheses

I'm trying to run this code:

picture = re.search("#4F9EFF;\"><img src=\"(.+?)\" wid开发者_JAVA技巧th=\"120\" height=\"90\"", data)

and when i do print picture.groups(1) it returns me the value but with parentheses, why?

Output:

('http://sample.com/img/file.jpg',)

---

The group is a tuple containing one element. You can access the string (which is the first match) as output[0]. The important part is the comma after the string.

BUT

DON'T PARSE HTML WITH REGEX

You should use a proper HTML parser. This will save you innumerable headaches in the future, when your regex fails to match or gets too much. Look into BeautifulSoup or lxml.

---

Notice the comma before the closing parenthesis? This is a tuple (albeit one with just one element in it).

As the documentation for MatchObject.groups() says:

groups([default])

Return a tuple containing all the subgroups of the match, from 1 up to however many groups are in the pattern. The default argument is used for groups that did not participate in the match; it defaults to None.

As noted by other posters, you want to use MatchObject.group() instead.

---

You should be using

picture.group(1)

not groups() in plural if you're only looking for one specific group. groups() always returns a tuple, group() is the one you're looking for.

---

groups() returns a tuple of all the groups. You want pictures.group(1) which returns the string that matched group 1.

---

As the groups help says is returns "a tuple containing all the subgroups of the match". If you want a single group use the group method.