How can I开发者_运维技巧 convert a time in the format "YYYY-MM-DD hh:mm:ss" (e.g. "2011-07-15 13:18:52"
) to a UNIX timestamp?
I tried this piece of Javascript code:
date = new Date("2011-07-15").getTime() / 1000
alert(date)
And it works, but it results in NaN
when I add time('2011-07-15 13:18:52') to the input.
Use the long date constructor and specify all date/time components:
var match = '2011-07-15 13:18:52'.match(/^(\d+)-(\d+)-(\d+) (\d+)\:(\d+)\:(\d+)$/)
var date = new Date(match[1], match[2] - 1, match[3], match[4], match[5], match[6])
// ------------------------------------^^^
// month must be between 0 and 11, not 1 and 12
console.log(date);
console.log(date.getTime() / 1000);
Following code will work for format YYYY-MM-DD hh:mm:ss
:
function parse(dateAsString) {
return new Date(dateAsString.replace(/-/g, '/'))
}
This code converts YYYY-MM-DD hh:mm:ss
to YYYY/MM/DD hh:mm:ss
that is easily parsed by Date
constructor.
You've accepted an answer, but a much simpler regular expression can be used:
function stringToDate(s) {
s = s.split(/[-: ]/);
return new Date(s[0], s[1]-1, s[2], s[3], s[4], s[5]);
}
alert(stringToDate('2011-7-15 20:46:3'));
Of course the input string must be the correct format.
Months start from 0, unlike the days! So this will work perfectly (tested)
function dateToUnix(year, month, day, hour, minute, second) {
return ((new Date(Date.UTC(year, month - 1, day, hour, minute, second))).getTime() / 1000.0);
}
This returns number of milliseconds since Jan. 1st 1970:
Date.parse('2011-07-15 10:05:20')
Just divide by 1000 to get seconds instead of milliseconds..
精彩评论