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get data by left join with count() for each row

开发者 https://www.devze.com 2023-03-20 12:57 出处:网络
My code: $q = mysql_query(\" SELECT ads.title_ad AS title_ad, COUNT(adclicks.ad_id) AS counted, ads.dclicks AS dclicks

My code:

$q = mysql_query("
            SELECT 
                ads.title_ad AS title_ad, 
                COUNT(adclicks.ad_id) AS counted, 
                ads.dclicks AS dclicks
            FROM ads
            LEFT JOIN adclicks 
                ON ads.id = adclicks.ad_id GROUP BY ads.id
   开发者_JAVA百科 ");

while($row = mysql_fetch_array($q))
{
    if($row['counted'] > $row['dclicks'])
    {
    }
    else
    {
        echo ''.$row['title_ad'].' '.$row['counted'].' '.$row['dclicks'].'<br>';
    }
}

I just want to remove if(){} and want to adjust it in sql query.

Whats the solution? How to do that?


Add a HAVING clause to your SQL:

HAVING COUNT(adclicks.ad_id) < ads.dclicks
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