ios obj C separate string into chars and add letters

How can I separate a string? For example, into开发者_如何学编程 e x a m p l e, and generate a summation sumatory with the defined value for each letter [ a=1, b =2, c=3,..z=26]

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You can use characterAtIndex to extract a specific character from your string, e.g.

[myString characterAtIndex:1]

Or loop through all:

for (int i=0; i < [myString length]; i++) {
    ... [myString characterAtIndex:i]
   // You can then decide how to assign a value to each individual string, via a switch.

}

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Here is a way to do so :

NSMutableArray *chars = [NSMutableArray arrayWithCapacity:26];
// fill the array
unsigned int i;
for(i = 0; i < 26; i++) {
    NSString *s = [NSString stringWithFormat:@"%c", (i+65)];
    [chars addObject:s];
}
// now you have [0:"a", 1:"b", ..., 25:"z"]
NSUInteger sum = 0;
NSString lowerCaseString = [myString lowerCaseString];
for (int i=0; i < [myString length]; i++) {
    NSString *character = [lowerCaseString substringWithRange:NSMakeRange(i, 1)];
    // edit thanks to mortenfast ;-)
    NSUInteger pos = [chars indexOfObject:character];
    if(pos != NSNotFound) {
        sum += (pos+1);
    }
}

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A block version for iOS 4.0:

__block int sum = 0;
NSString *string = [NSString stringWithString:@"abcdefghijklmnopqrstuvwxyz"];
[string enumerateSubstringsInRange:NSMakeRange(0,[string length]) 
                           options:NSStringEnumerationByComposedCharacterSequences 
                        usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {

    // 'a'=97=0x61=01100001, 'A'=65=0x41=01000001
    // 26 letters and 2^5-1=31 so only 5 lower bits needed
    sum += [substring characterAtIndex:0] & 0x1F;

    // which is the same as
    // sum += [substring characterAtIndex:0] -'a'+1;

}];