How can I create an alphanumeric Regex for all languages?

I had this problem today:

This regex matches only English: [a-zA-Z0-9].

If I need support for any开发者_StackOverflow language in this world, what regex should I write?

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If you use character class shorthands and a Unicode aware regex engine you can do that. The \w class matches "word characters" (letters, digits, and underscores).

Beware of some regex flavors that don't do this so well: JavaScript uses ASCII for \d (digits) and \w, but Unicode for \s (whitespace). XML does it the other way around.

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Alphabet/Letter: \p{L}

Number: \p{N}

So for alphnum match for all languages, you can use: [\p{L}\p{N}]+

I was looking for a way to replace all non-alphanum chars for all languages with a space in JS and ended up using the following way to do it:

const regexForNonAlphaNum = new RegExp(/[^\p{L}\p{N}]+/ug);
someText.replace(regexForNonAlphaNum, " ");

Here as it is JS, we need to add u at end to make the regex unicode aware and g stands for global as I wanted match all instances and not just a single instance.

References:

https://www.linkedin.com/pulse/regex-one-pattern-rule-them-all-find-bring-darkness-bind-carranza/?trackingId=U6tRte%2BzTAG6O4AA3CrFmA%3D%3D

https://www.regular-expressions.info/unicode.html

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Regex supporting most languages

^[A-zÀ-Ÿ\d-]*$

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The regex below is the only one worked for me:

"\\p{LD}+" ==> LD means any letter or digit. 

If you want to clean your text from any non alphanumeric characters you can use the following:

text.replaceAll("\\P{LD}+", "");//Note P is capital.