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How do you create foreign keys in attached sqlite databases?

开发者 https://www.devze.com 2023-03-20 06:42 出处:网络
I am trying to create a sqlite3 database as a test environment that mimics the production environment.Due to the way production is setup the tables are in multiple schemas.

I am trying to create a sqlite3 database as a test environment that mimics the production environment. Due to the way production is setup the tables are in multiple schemas.

I have setup the classes in DBIx::Class, using $schema->storage->dbh_do to attach the database with the schema, and using $schema-deploy() to create the database.

However when it comes to creating the foreign key on the second table I get the following error:

DBIx::Class::Schema::deploy(): DBIx::Class::Schema::deploy(): DBI Exception: DBD::SQLite::db do failed: near ".": syntax error 

Taking away DBIx::Class the simplest test to reproduce is as follows.

sqlite3 initial.db
SQLite version 3.6.23
Enter ".help" for instructions
Enter SQL statements terminated with a ";"   
sqlite> attach database 'other.db' as 'other';
sqlite> create table other.a( col1_a, col2_a);
sqlite> create table other.b( col1_b, col2_b, foreign key(col1_b) references other.a(col1_a));
Error: near ".": syntax error
sqlite> create table other.b( col1_b, col2_b, foreign key(col1_b) references a(col1_a));
sqlite> 

Removing the schema from the foreign key clause will successfully create the table.

How can i create the tables in the foreign schema with DBIx::Class?

EDIT: A full sample of the code.

package MyApp::Schema;
use base qw/DBIx::Class::Schema/;
__PACKAGE__->load_namespaces();
1;


package MyApp::Schema::Result::A;
use base qw/DBIx::Class::Core/;
__PACKAGE__->table('other_db.A');
__PACKAGE__->add_columns(qw/ a1 a2 /);
__PACKAGE__->set_primary_key('a1');
__PACKAGE__->has_many(bs => 'MyApp::Schema::Result::B', 'b1');
1;

package MyApp::Schema::Result::B;
use base qw/DBIx::Class::Core/;
__PACKAGE__->table('other_db.B');
__PACKAGE__->add_columns(qw/ b1 b2 /);
__PACKAGE__->set_primary_key('b1');
__PACKAGE__->belongs_to(a => 'MyApp::Schema::Result::A', 'b1');
1;

The main script:

use MyApp::Schema;

my $schema = MyApp::Schema->connect('dbi:SQLite:dbname=test.db','','',{});

my $res = $schema->storage->dbh_do(
   开发者_JAVA技巧 sub {
        my ($storage, $dbh) = @_;
        $dbh->do("attach database 'other.db' as other_db");
    }
);

$schema->deploy();

The error given is:

DBIx::Class::Schema::deploy(): DBIx::Class::Schema::deploy(): DBI Exception: DBD::SQLite::db do failed: near ".": syntax error [for Statement "CREATE TABLE other_db.B (
  b1  NOT NULL,
  b2  NOT NULL,
  PRIMARY KEY (b1),
  FOREIGN KEY(b1) REFERENCES other_db.A(a1)
)"] at dbi.pl line 17
 (running "CREATE TABLE other_db.B (
  b1  NOT NULL,
  b2  NOT NULL,
  PRIMARY KEY (b1),
  FOREIGN KEY(b1) REFERENCES other_db.A(a1)
)") at dbi.pl line 17


Simple answer is that you can't (and don't need to) specify the database name when with the table name in foreign key definitions. The sqlite docs indicates it as such.

This link shows how you can use the database name with the new table name in the "create table db.table" part:

http://www.sqlite.org/lang_createtable.html

Whereas this link shows how you can't use the database name in the foreign key definition:

http://www.sqlite.org/syntaxdiagrams.html#foreign-key-clause

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