I have table tblTask with data like below.
TID StartTime 开发者_StackOverflow社区 Uid WId
1 2011-06-06 09:30:00.000 10 1.5
2 2011-06-06 09:40:00.000 10 2.5
3 2011-06-06 09:50:00.000 10 1.8
4 2011-06-06 09:55:00.000 10 2.5
5 2011-06-06 10:30:00.000 10 1.5
6 2011-06-06 11:30:00.000 11 3.0
I need to write to query to calculate sum(Wid) based on time difference of each Starttime with another starttime having time difference 1 hour or close to 1 hr.
For example take first start time(2011-06-06 09:30:00.000); the nearest start time having <=1 hr is (2011-06-06 10:30:00.000) and the SUM(Wid) is 1.5+2.5+1.8+2.5+1.5 = 9.8. Likewise I need to calculate for all rows.
Desired output will be:
TID StartTime EndTime TimeDIff(Min) Uid WId
1 2011-06-06 09:30:00.000 2011-06-06 10:30:00.000 60 10 9.8
2 2011-06-06 09:40:00.000 2011-06-06 10:30:00.000 50 10 8.3
Does this give you what you need?
SELECT t1.TID, min(t1.StartTime) AS StartTime, MAX(t2.StartTime) AS EndTime,
MAX(DATEDIFF(MI, t1.StartTime, t2.StartTime)) AS [TimeDiff(Min],
t1.Uid, SUM(t2.WId) AS WId
FROM MyTable t1
JOIN MyTable t2 on datediff(MI, t1.starttime, t2.StartTime) BETWEEN 0 AND 60
GROUP BY t1.TID, t1.Uid
ORDER BY t1.TID
This block of code will give you the time difference between StartTime
and EndTime
DECLARE @STARTDATE DATETIME = '10:15:45'
DECLARE @ENDDATE DATETIME = '14:00:15'
DECLARE @24DATE DATETIME
SET @24DATE = '23:59:59.000'
IF (@STARTDATE > @ENDDATE)
SELECT DATEADD(SECOND, 1, CONVERT(TIME(0), (@24DATE -(@ENDDATE - @STARTDATE))))
ELSE
SELECT CONVERT(TIME(0), ((@ENDDATE - @STARTDATE)))
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