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Creating an instance of variable with reflection

开发者 https://www.devze.com 2022-12-15 09:45 出处:网络
I want to create an instance of type t with reflection, that is Type t = typeof(string); string s = (t)Activator.CreateInstance(t); // this fails because of convertion

I want to create an instance of type t with reflection, that is


Type t = typeof(string);
string s = (t)Activator.CreateInstance(t); // this fails because of convertion
string s = Activator.CreateInstance(t) as t // als开发者_如何学Goo fails

Is there a way to perform such a convertion? Thanks.


Yes. You have to convert to string, not to t. You may want a generic method, alternatively:

public T GetInstance<T>()
{
    Type t = typeof(T);
    T s = (T)Activator.CreateIstance(t);
    return s;
}

As things stand you are attempting to cast an object that is actually an instance of System.String to type System.Type...


Try this:

string s = (string)Activator.CreateInstance(t);

Activator.CreateInstance returns an instance boxed in an object so it must be cast to the correct type before you can use it.

In your example t is a Type object variable and not a type reference. You must either specify the type directly as in my example or you can use generics.

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