I'm going through an HTML file replacing all the references to external files with new ones, however, sometimes this results in errors.
For example: I want to replace all instances of styles.css with 1.css and all instances of iestyles.css with 2.css in this source code:
<html>
<link href="styles.css" />
<link href="iestyles.css" />
</html>
Once I've run str_replace("styles.css"开发者_StackOverflow, "1.css", $html); the source code looks like this:
<html>
<link href="1.css" />
<link href="ie1.css" />
</html>
So when I run the second query, it doesn't change the iestyles.css reference because it no longer exists. Is there a way around this? I guess I could invent an elaborate regular expression, but there are a lot of variables to consider because not all code is well formed.
Cheers
Just change the order: First replace iestyles.css with 2.css and then replace styles.css with 1.css.
If you are sure the filename is the only thing within the href-attribut, you could also include the double quotes "
$html = str_replace('"styles.css"', '"1.css"', $html);
$html = str_replace('"iestyles.css"', '"2.css"', $html);
Including the double quotes (assuming they all use double quotes) should work.
str_replace('"styles.css"', '"1.css"', $html);
use preg_replace();
preg_replace('|<link href="styles\.css" />|', '1.css', $html);
or just prepend double quotes before styles
str_replace('"styles.css', '"1.css', $html);
Just include the quotes in your replacement.
replace "styles.css" with "1.css"
You could change 'iestyles.css' first.
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