I have created a jtree with the root node "RootNode" and some other n开发者_开发百科odes like "Node1","Node2", Node3".
After creation of tree I want to rename the rootnode or any other node by manually. We can rename the node dynamically by using the method
jtee.setEditable(true);
But I want to change the name in manualy by the code level
like
someMethod(Arg1 oldNodeName,Arg2 newNodeName)
Is there any way to do this?
Assuming you are using a DefaultMutableTreeNode you could just change the UserObject (whose toString() method is what is used to display the node name) by calling: setUserObject()
on the node you want to change.
I'll assume you're using a tree with a DefaultTreeModel
, using instances of DefaultMutableTreeNode
.
You'll have to iterate through the tree nodes and find the one which has the oldNodeName
as user object, then change its user object to newNodeName
, and call the method nodeChanged
of the tree model.
To properly rename a DefaultMutableTreeNode
, you must set it's new user object as well as notify the JTree
s table model the node changed so it can resize it for the shorter/longer text.
Assuming your tree is using a DefaultTreeModel
, use this:
public void renameNode(JTree tree, DefaultMutableTreeNode node, Object new_user_object) {
node.setUserObject(new_user_object);
((DefaultTreeModel) tree.getModel()).nodeChanged(node);
}
It does change the UI, if:
- you are using a DefaultTreeModel model
- you actually change the UserObject
This is to say something like this:
// TheNode is a CustomMutableTreeNode (extending DefaultMutableTreeNode)
// and points to the selected node to alter
String NewNodeName = Dlg.NewNodeName.getText();
if(!NewNodeName.isEmpty()) {
ON.setName(NewNodeName); // ON is the real source data
TheNode.setUserObject(NewNodeName);
((DefaultTreeModel)JSONTree.getModel()).nodeChanged(TheNode);
}
It took me quite a while to figure out that changing the source data (in ON) did nothing on the UI, even with a repaint();. You really have to update theUserObject (a String from the DefaultMutableTreeNode)
Once this done, it's the easiest and most elegant solution IMO.
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