开发者

Gather div class into a javascript array

开发者 https://www.devze.com 2023-03-19 05:43 出处:网络
My current html looks like this: <div class=\"wrapper\" style=\"display:block;\" id=\"item0\"><!--- Stuff --></div>

My current html looks like this:

<div class="wrapper" style="display:block;" id="item0"><!--- Stuff --></div>
<div class="wrapper" style="display:none;" id="item1"><!--- Stuff --></div>
<div class="wrapper" style="display:none;" id="item2"><!--- Stuff --></div>
<div class="wrapper" style="display:none;" id="item3"><!--- Stuff --></div>
<div class="wrapper" style="display:none;" id="item4"><!--- Stuff --></div>

And then I have a back/forward link which call the corresponding javascript function, it looks like this:

 function switchNextItem() {  
    var element0 = document.getElementById('item0');
    var element1 = document.getElementById('item1');
    var element2 = document.getElementById('item2');
    var element3 = document.getElementById('item3');
    var element4 = document.getElementById('item4');

    if (element0.style.display == 'block')  {
        element0.style.display = 'none';  
        element1.style.display = 'block';
    } else if (element1.style.display == 'block') {
        element1.style.display = 'none';
        element2.style.display = 'block';
    } else if (element2.style.display == 'block') {
        element2.style.display = 'none';
        element3.style.disp开发者_StackOverflow社区lay = 'block';
    } else if (element3.style.display == 'block') {
        element3.style.display = 'none';
        element4.style.display = 'block';
    } else if (element4.style.display == 'block') {
        element4.style.display = 'none';
        element0.style.display = 'block';
    }
} 

Are there any possibilities for me to make this more dynamically?

Thanks! (I'm not familiar with javascript).


You'd love jQuery: http://jsfiddle.net/TCQum/.

function switchNextItem() {
    $('div.wrapper:visible')  .hide()    .next()      .show();
//     select visible div   | hide it | goto next | show that one
}

Edit: A more precise one:

function switchNextItem() {
    var next = $('div.wrapper:visible:eq(0)')
               .hide()
               .next('div.wrapper'); // next one will be stored in next

    if(next.length === 0) { // if there is no next one, show first one agan
        $('div.wrapper:eq(0)').show();
    } else { // otherwise show next one
        next.show();
    }
}

And with .prev:

function switchNextItem() {
    var prev = $('div.wrapper:visible:eq(0)')
               .hide()
               .prev('div.wrapper'); // prev one will be stored in prev

    if(prev.length === 0) { // if there is no prev one, show last one
        $('div.wrapper:last').show();
    } else { // otherwise show prev one
        prev.show();
    }
}


Something like this should work.

function switchNextItem() {  
    var items=['item0','item1','item2','item3','item4'];

    for(var i=0;i<items.length;i++){
        var element = document.getElementById(items[i]);

        if (element.style.display == 'block')  {
            element.style.display = 'none';  

            var nextElement = document.getElementById(items[(i+1) % items.length]);
            nextElement.style.display = 'block';

            break;
        }
    }
} 
0

精彩评论

暂无评论...
验证码 换一张
取 消