I am pretty new to Django (starting with 1.3). In building an app, I went with the new class-ba开发者_运维问答sed generic views from day one, using a combination of the built in classes and subclassing them where I needed to add to the context.
Now my problem is, I need to go back to my views, and have them accessible only to logged in users. ALL the documentation I have found shows how to do this with the old functional generic views, but not with class-based.
Here is an example class:
class ListDetailView(DetailView):
context_object_name = "list"
def get_queryset(self):
list = get_object_or_404(List, id__iexact=self.kwargs['pk'])
return List.objects.all()
def get_context_data(self, **kwargs):
context = super(ListDetailView, self).get_context_data(**kwargs)
context['subscriber_list'] = Subscriber.objects.filter(lists=self.kwargs['pk'])
return context
How do I add authentication to django's new class-based views?
There's also the option of an authentication mixin, which you would derive your view class from. So using this mixin from brack3t.com:
class LoginRequiredMixin(object):
@method_decorator(login_required)
def dispatch(self, *args, **kwargs):
return super(LoginRequiredMixin, self).dispatch(*args, **kwargs)
you could then create new "authentication required" views like this:
from django.views.generic import DetailView
class MyDetailView(LoginRequiredMixin, DetailView):
....
with no other additions needed. Feels very much like Not Repeating Oneself.
There's a section in the docs on decorating class-based views -- if you just want to use the old login_required
etc., that's the way to go.
I am describing a method to decorate any ListView :
class MyListView(ListView):
decorator = lambda x: x
@method_decorator(decorator)
def dispatch(self, request, *args, **kwargs):
return super(MyListView, self).dispatch(request, *args, **kwargs)
After writing a class based view like this, you can directly insert any function based decorator into the url as so.
url(r'^myurl/$', MyListView.as_view(decorator=login_required))
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