I am embedding Python in a C++ library which I am making. I would like users to be able to pass C functions in the form of function pointers PyObject* (fpFunc*)(PyObject*,PyObject*);
so that I can use those functions in the embedded Python.
So I have a function pointer and I know that it is possible to put this function as a module's method using a PyMethodDef
struct and passing it to Py_InitModule("module", ModMethods);
and thus obtaining a PyObject* module
which I can easily grab functions from.
But, what I would开发者_如何学编程 really appreciate is to be able to create this function on the fly without necessarily recreating another module each time.
I have looked into the Python docs, and some of the Python headers to think about a hacky way of doing this without real success... but I'm wondering if's there's a more conventional way of doing this.
From what I understood, every function belongs to a module, even __builtin__
, so I guess I would require at least on module.
Any idea on how to achieve this?
Found it. Though it's not in the docs and it's hardly explicit in the source.
PyObject* (*fpFunc)(PyObject*,PyObject*) = someFunction;
PyMethodDef methd = {"methd",fpFunc,METH_VARARGS,"A new function"};
PyObject* name = PyString_FromString(methd.ml_name);
PyObject* pyfoo = PyCFunction_NewEx(&methd,NULL,name);
Py_DECREF(name);
It works. I can call the function like I normally would call a Python function object.
If you're curious, all I found in the doc was about Py_InitModule4
and loading modules, so I went to check Python's source, and found out about PyCFunction
, then I looked around in the doc but I couldn't find anything about PyCFunction_NewEx
, so I had to check the source to make sure it was as I thought.
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