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syntax error on line: `if x.isupper() and not in y`

开发者 https://www.devze.com 2023-03-19 02:10 出处:网络
I\'m getting \"invalid syntax\" errors pointing to the \"in\" statement. What\'s my mistake? while(notes > 1):

I'm getting "invalid syntax" errors pointing to the "in" statement. What's my mistake?

while(notes > 1):
    note = choice(scale)
    if note[0].isupper() and not in patternNotes:
        patternNotes.append(note)
        开发者_Python百科notes -= 1

    elif note is not rootNote and note not in patternNotes:
        patternNotes.append(note)
        notes -= 1


You probably want

if note[0].isupper() and note not in patternNotes:

rather than

if note[0].isupper() and not in patternNotes:

Note the lacking note in the second one.


It should be note[0].isupper() and note not in patternNotes: (notice the second note before not)

After that your syntax is fine:

i = {}
j = {}
print i is not j and j not in {}
# False


Note that this is an infinite loop under certain conditions, like "note in patternNotes". Move the "notes -= 1" statement outside the if/elif and the problem is solved.

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