>str(set)
'data.frame': 1000 obs. of 6 variables:
$ ID : Factor ..
$ a : Factor ..
$ b: Factor ..
$ c: Factor ..
$ dat : num ..
$ contrasts : Ord.factor ..
>X
[1] "a" "b" "c"
for (i in 1 :length(X) ){
my=X[i]
f=as.formula(paste("dat~contrasts*", paste(my,"Error(ID/(contrasts))",sep="+")))
sum = summary( aov (f, data =set))
}
X can be very huge, so was thinking about an apply function instead of for-loop.Is it possible in this case??
I tried this:
apply(
as.matrix(X), 1, function(i){
summary(aov(as.formula(paste("dat~contrasts*",
paste(i, "Error(ID/(contrasts))"开发者_StackOverflow中文版, sep="+"))), data=set))
}
)
But this makes no sense. Can anyone help me?
This ought to do it:
# Sample data
set <- data.frame(ID=1:10, a=letters[1:10], b=LETTERS[1:10], c=letters[10:1],
dat=runif(10), contrasts=ordered(rep(1:2, 5)))
X <- letters[1:3] # a,b,c
sapply(X, function(my) {
f <- as.formula(paste("dat~contrasts*",my,"+Error(ID/(contrasts))"))
summary(aov(f, data=set))
}, simplify=FALSE)
Note the use of sapply with simplify=FALSE. Using lapply also works, but it doesn't add names to the list components.
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