Get <img>'s title-attribute with lxml in Python

I want to extract the onel-iner-texts from this website using Python. The messages in HTML look like this:

<div class="olh_message"> 
    <p>foobarbaz <img src="/static/emoticons/support-our-fruits.gif" title=":necta:" /></p> 
</div> 

My code looks like this so far:

import lxml.html
url = "http://www.scenemusic.net/demovibes/oneliner/"
xpath = "//div[@class='olh_message']/p"
tree = lxml.html.parse(url)
texts = tree.xpath(xpath)
texts = [text.text_content() for text in texts]
print(texts)

Now, however, I only get foobarbaz, I however would like to get the title-argument of the img's in it as well, so in this example foobarbaz :necta:. It seems I need lxml's DOM 开发者_高级运维parser to do it, however I have no idea how. Anyone can give me a hint?

Thanks in advance!

---

try this

  import lxml.html
  url = "http://www.scenemusic.net/demovibes/oneliner/"
  parser = lxml.etree.HTMLParser()
  tree = lxml.etree.parse(url, parser)
  texts = tree.xpath("//div[@class='olh_message']/p/img/@title")

---

Use:

//div[@class='olh_message']/p/node()

his selects all children nodes (elements, text-nodes, PIs and comment-nodes) of any p element that is a child of any div element, whose class attribute is 'olh_message'.

Verification using XSLT as the host of XPath:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="/">
     <xsl:copy-of select="//div[@class='olh_message']/p/node()"/>
 </xsl:template>
</xsl:stylesheet>

when this transformation is applied on the following XML document:

<div class="olh_message">
    <p>foobarbaz 
        <img src="/static/emoticons/support-our-fruits.gif" title=":necta:" />
    </p>
</div>

the wanted, correct result is produced (showing that exactly the wanted nodes have been selected by the XPath expression):

foobarbaz 
        <img src="/static/emoticons/support-our-fruits.gif" title=":necta:"/>