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Why the bullseye code coverage doesn't trace a pure virtual function of inherited class?

开发者 https://www.devze.com 2023-03-18 18:40 出处:网络
I met a problem about the Bullseye code coverage. It\'s a tracing ability of the program. The following code is not traced.

I met a problem about the Bullseye code coverage. It's a tracing ability of the program. The following code is not traced.

class A
{
public:
    virtual void func() = 0;
};

class B
{
public:
    virtual void func()
    {
         std::cout << "Am I traced?" << std::endl;
    }
};

void main()
{
    A *pa = new B;
   开发者_如何学运维 pa->func();
}

I guess that Bullseye may not trace pure virtual function. If there are someone who has a knowledge about the program, please give me some advice.


You have 2 errors, in the given program:

void func() = 0;

should be,

virtual void func() = 0;

And,

class *pa = new B;

should be,

class B *pa = new B;  // `class` keyword not needed

Also, note that A and B are not related (no inheritance).

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