I am trying to figure out how to write a simple if condition in nant that will evaluate to true when both x & y properties are true.
<project default="all">
<property name="x" value="True" />
<property name="y" value="True" />
<target name="all">
<echo message="x is True" if="${x}" />
<echo message="y is True" if="${x}" />
<echo message="x AND y are True" if开发者_开发技巧="${x} AND ${y}" />
<echo message="x AND y are True" if="${x} && ${y}" />
</target>
</project>
I cannot figure out the syntax for the x AND y echo message - I tried both AND and '&&' and that doesn't seem to work.(i keep getting error messages like : String was not recognized as a valid Boolean.)
You want to use if="${x and y}", where both x and y are in the same pair of brackets:
<project default="all">
<property name="x" value="true" />
<property name="y" value="true" />
<target name="all">
<echo message="x is True" if="${x}" />
<echo message="y is True" if="${y}" />
<echo message="x AND y are True" if="${x and y}" />
</target>
</project>
Hope that helps!
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