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better way to read xml

开发者 https://www.devze.com 2023-03-18 00:16 出处:网络
I have xml file <root> <child_1> <sub_child attr1=\"text\" attr2=\"text\" /> <sub_child attr1=\"text\" attr2=\"text\" />

I have xml file

<root>
  <child_1>
    <sub_child attr1="text" attr2="text" />
    <sub_child attr1="text" attr2="text" />
    <sub_child attr1="text" attr2="text" />
  </child_1>    
  <child_2>
    <sub_child attr1="text" attr2="text" />
    <sub_child attr1="text" attr2="text" />
    <sub_child attr1="text" attr2="text" />
  </child_2>    
  <child_3>
    <sub_child_1 attr1="text" attr2="text" />
    <sub_child_2 attr1="text" attr2="text" />
  </child_3>    
  ...

and I want to read sub_child attributes to classes

class SubChild开发者_StackOverflow {
  string a1;
  string a2;
}

I need two lists of SubChild objects for child_1 and child_2 and two SubChild objects for sub_child_1 and sub_child_2

Now I use linq to xml and my code is

// List<SubChild> 
var child_1 = from s in doc.Descendants("sub_child").Where(x => x.Parent.Name == "child_1")
              select new SubChild {
                a1 = s.Attribute("attr1").Value,
                a2 = s.Attribute("attr2").Value,
              };

// List<SubChild> 
var child_2 = from s in doc.Descendants("sub_child").Where(x => x.Parent.Name == "child_2")
              select new SubChild {
                a1 = s.Attribute("attr1").Value,
                a2 = s.Attribute("attr2").Value,
              };

// SubChild
var sub_1 = (from s in doc.Descendants("sub_child_1")
              select new SubChild {
                a1 = s.Attribute("attr1").Value,
                a2 = s.Attribute("attr2").Value,
              }).First();

// SubChild
var sub_2 = (from s in doc.Descendants("sub_child_2")
              select new SubChild {
                a1 = s.Attribute("attr1").Value,
                a2 = s.Attribute("attr2").Value,
              }).First();

but it looks ugly and I would like to ask is there more clear way to do this?


You can specify a "Path" using .Element() and .Elements(), eliminating the where lambdas.

 // untested
 var child_1 = from s in doc.Root.Element("child_1").Elements("sub_child")
          select new SubChild {
            a1 = s.Attribute("attr1").Value,
            a2 = s.Attribute("attr2").Value,
          };


To go a couple of steps further, you could create a dictionary containing all the subchildren of your elements. This will allow you direct access to the SubChild's of each element by name.

Dictionary<string, List<SubChild>> dict = doc.Root.Elements().ToDictionary(
    e => e.Name.ToString(),
    e => e.Elements("sub_child")
          .Select(s => new SubChild
                       {
                           a1 = s.Attribute("attr1").Value,
                           a2 = s.Attribute("attr2").Value,
                       }).ToList());
dict["child_1"][0] // get the first subchild of "child_1"


Do you really have to use linq to xml?

public IEnumerable<SubChild> GetSubChilds(XmlDocument xd)
{
   foreach (XmlNode subChild in xd.SelectNodes("/root/*/*"))
   {
       if (subChild.Name.StartsWith("sub_child"))
       {
           XmlAttributeCollection atts = subChild.Attributes;
           yield return new SubChild { a1 = atts["attr1"].Value, a2 = atts["attr2"].Value };
       }
   }
}
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