Sorry for the newbie question, but i cannot find an answer to it.
I have a simple oper开发者_如何学Goation. I declare a variable, and then i want to loop through an array of integers and add these to the variable. However, i can't seem to find how to get a += equivalent going in Objective C.
Any help would be awesome.
Code:
NSInteger * result;
for (NSInteger * hour in totalhours)
{
result += hour;
}
NSInteger
is not a class, it's a typedef
for int
. You cannot put it into collections like NSArray
directly.
You need to wrap your basic data types (int
, char
, BOOL
, NSInteger
(which expands to int
)) into NSNumber
objects to put them into collections.
NSInteger
does work with +=
, keep in mind that your code uses pointers to them, which is probably not what you want anyway here.
So
NSInteger a = 1, b = 2;
a += b;
would work.
If you put them with [NSNumber numberWitInt:a];
etc. into an NSArray
, this is not that easy and you need to use -intValue
methods to extract their values first.
If totalhours actually contains NSNumber objects you need the following:
NSInteger result = 0;
for(NSNumber* n in totalhours)
{
result += [n integerValue];
}
The problem is that you are confusing NSInteger (a typedef for int
or long
) with a class instance such as NSNumber
.
If your totalhours
object is an array of NSNumber
objects, you'll need to do:
NSInteger result;
for (NSNumber *hour in totalhours)
{
result += [hour integerValue];
}
No problem using the '+=' operator, just be sure about the objects you are working with... Your code might be :
NSNumber *n; NSUInteger t = 0;
for(n in totalHours) {
t += [n integerValue];
}
// you got your total in t...
The += operation definitly works. All you need to do is initialize your result
variable so it has a start value.
E.g. NSInteger * result = 0;
Good luck!
Your problem is probably that you're using a pointer to an NSInteger instead of an actual NSInteger. You're also not initializing it. Try this:
NSInteger result = 0;
for (NSInteger * hour in totalhours)
{
result += *hour;
}
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