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regex which accept positive integer and nothing

开发者 https://www.devze.com 2023-03-17 11:20 出处:网络
hi I found on the Internet that this regexp accept positive number ^\\d+$a开发者_JS百科nd this accept nothing ^$

hi I found on the Internet that this regexp accept positive number ^\d+$ a开发者_JS百科nd this accept nothing ^$ So no I wanna combine this two regexp but with no success. I try this (^\d+$)|(^$) but this didnt work. So help me with regexp which accept positive integer and nothing thx a lot


Simply do:

^\d*$

The * means: "zero or more times".

Since you've asked most questions with the Java tag, I'm assuming you're looking for a Java solution. Note that inside a string literal, the \ needs to be escaped!

A demo:

class Test {
  public static void main(String[] args) {
    String[] tests = {"-100", "", "2334", "0"};
    for(String t : tests) {
      System.out.println(t + " -> " + t.matches("\\d*"));
    }
  }
}

produces:

-100 -> false
 -> true
2334 -> true
0 -> true

Note that matches(...) already validates the entire input string, so there's no need to "anchor" it with ^ and $.

Beware that it would also return true for numbers that exceed Integer.MAX_VALUE and Long.MAX_VALUE. SO even if matches(...) returned true, parseInt(...) or parseLong(...) may throw an exception!


Try ^[0-9]*$ . This one allows numbers and nothing.


How about ^\d*$? That would accept a sequence of digits (i.e. a positive integer) by itself in a line without whitespace or an empty line.

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