Let me set up an example:
from BeautifulSoup import BeautifulStoneSoup
root = ''' <all2>
<images>
<image>
<name> Picture </name>
<url> www.thing.com</url>
</image>
<image>
<name> Another one! </name>
</image>
</images>
</all2>
'''
soup = BeautifulStoneSoup(root)
for img in soup.all2.images.findAll("image"):
iname = img.i_name
iurl = img.url
print ina开发者_运维问答me
print iurl
Let the tag be optional. In this case, the second iteration will fail to to find a tag, and an exception will be thrown:
AttributeError: 'NoneType' object has no attribute 'renderContents'
I would like for iurl to be None if an optional tag does not appear. Is this possible? Or is my XML understanding wrong.
What do you want with 'nameTag'???
The BeautifulSoup documentation clearly tells you to use
iname = img.name.renderContents()
iurl = img.url.renderContents()
Zero reason to invent new syntax or semantics here
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