Im a JQUery noob and just had a question about a slider I have used which is based on this one: http://www.dreamcss.com/2009/04/create-beautiful-jquery-sliders.html
I have altered the CSS to adjust to the slider I am using and everything looks fine. What happens currently is that I have 7 images which all slide towards the left, when it goes to the end of the loop/7th image, it slides towards the right showing all of the images from 1-7 until goes back to image 1 and then starts the sliding loop again.
What I am trying to do is make image 7 go to image 1 towards the left as so it is a continuous loop and not one that goes back to the start. Any suggestions?
PS. I am using jquery 1.2.6
window.onerror=function(desc,page,line,chr){
/* alert('JavaScript error occurred! \n'
+'\nError description: \t'+desc
+'\nPage address: \t'+page
+'\nLine number: \t'+line
);*/
}
$(function(){
$('a').focus(function(){this.blur();});
SI.Files.stylizeAll();
slider.init();
$('input.text-default').each(function(){
$(this).attr('default',$(this).val());
}).focus(function(){
if($(this).val()==$(this).attr('default'))
$(this).val('');
}).blur(function(){
if($(this).val()=='')
$(this).val($(this).attr('default'));
});
$('input.text,textarea.text').focus(function(){
$(this).addClass('textfocus');
}).blur(function(){
$(this).removeClass('textfocus');
});
var popopenobj=0,popopenaobj=null;
$('a.popup').click(function(){
var pid=$(this).attr('rel').split('|')[0],_os=parseInt($(this).attr('rel').split('|')[1]);
var pobj=$('#'+pid);
if(!pobj.length)
return false;
if(typeof popopenobj=='object' && popopenobj.attr('id')!=pid){
popopenobj.hide(50);
$(popopenaobj).parent().removeClass(popopenobj.attr('id').split('-')[1]+'-open');
popopenobj=null;
}
return false;
});
$('p.images img').click(function(){
var newbg=$(this).attr('src').split('bg/bg')[1].split('-thumb')[0];
$(document.body).css('backgroundImage','url('+_siteRoot+'images/bg/bg'+newbg+'.jpg)');
$(this).parent().find('img').removeClass('on');
$(this).addClass('on');
return false;
});
$(window).load(function(){
$.each(css_ims,function(){(new Image()).src=_siteRoot+'css/images/'+this;});
$.each(css_cims,function(){
var css_im=this;
$.each(['blue','purple','pink','red','grey','green','yellow','orange'],function(){
(new Image()).src=_siteRoot+'css/'+this+'/'+css_im;
});
});
});
$('div.sc-large div.img:has(div.tml)').each(function(){
$('div.tml',this).hide();
$(this).append('<a href="#" class="tml_open"> </a>').find('a').css({
left:parseInt($(this).offset().left)+864,top:parseInt($(this).offset().top)+1
}).click(function(){
$(this).siblings('div.tml').slideToggle();
return false;
}).focus(function(){this.blur();});
});
});
var slider={
num:-1,
cur:0,
cr:[],
al:null,
at:10*450,
ar:true,
init:function(){
if(!slider.data || !slider.data.length)开发者_运维问答
return false;
var d=slider.data;
slider.num=d.length;
var pos=Math.floor(Math.random()*1);//slider.num);
for(var i=0;i<slider.num;i++){
$('#'+d[i].id).css({left:((i-pos)*1000)});
$('#slide-nav').append('<a id="slide-link-'+i+'" href="#" onclick="slider.slide('+i+');return false;" onfocus="this.blur();">'+(i+1)+'</a>');
}
$('img,div#slide-controls',$('div#slide-holder')).fadeIn();
slider.text(d[pos]);
slider.on(pos);
slider.cur=pos;
window.setTimeout('slider.auto();',slider.at);
},
auto:function(){
if(!slider.ar)
return false;
var next=slider.cur+1;
if(next>=slider.num) next=0;
slider.slide(next);
},
slide:function(pos){
if(pos<0 || pos>=slider.num || pos==slider.cur)
return;
window.clearTimeout(slider.al);
slider.al=window.setTimeout('slider.auto();',slider.at);
var d=slider.data;
for(var i=0;i<slider.num;i++)
$('#'+d[i].id).stop().animate({left:((i-pos)*950)},950,'swing');
slider.on(pos);
slider.text(d[pos]);
slider.cur=pos;
},
on:function(pos){
$('#slide-nav a').removeClass('on');
$('#slide-nav a#slide-link-'+pos).addClass('on');
},
text:function(di){
slider.cr['a']=di.client;
slider.cr['b']=di.desc;
slider.ticker('#slide-client span',di.client,0,'a');
slider.ticker('#slide-desc',di.desc,0,'b');
},
ticker:function(el,text,pos,unique){
if(slider.cr[unique]!=text)
return false;
ctext=text.substring(0,pos)+(pos%2?'-':'_');
$(el).html(ctext);
if(pos==text.length)
$(el).html(text);
else
window.setTimeout('slider.ticker("'+el+'","'+text+'",'+(pos+1)+',"'+unique+'");',30);
}
};
// STYLING FILE INPUTS 1.0 | Shaun Inman <http://www.shauninman.com/> | 2007-09-07
if(!window.SI){var SI={};};
SI.Files={
htmlClass:'SI-FILES-STYLIZED',
fileClass:'file',
wrapClass:'cabinet',
fini:false,
able:false,
init:function(){
this.fini=true;
},
stylize:function(elem){
if(!this.fini){this.init();};
if(!this.able){return;};
elem.parentNode.file=elem;
elem.parentNode.onmousemove=function(e){
if(typeof e=='undefined') e=window.event;
if(typeof e.pageY=='undefined' && typeof e.clientX=='number' && document.documentElement){
e.pageX=e.clientX+document.documentElement.scrollLeft;
e.pageY=e.clientY+document.documentElement.scrollTop;
};
var ox=oy=0;
var elem=this;
if(elem.offsetParent){
ox=elem.offsetLeft;
oy=elem.offsetTop;
while(elem=elem.offsetParent){
ox+=elem.offsetLeft;
oy+=elem.offsetTop;
};
};
};
},
stylizeAll:function(){
if(!this.fini){this.init();};
if(!this.able){return;};
}
};
I tested the script and the example and found that it can not loop back to image 1 with effect slide towards to the left. Because the images were queued from left to right as 1-2-3-4-5-6-7, whenever it slide from image 7 to 1, it must turn back to the image 1 position (CSS left:6000px
to left:0px
). If you want the transition effect slide towards to the left, there will have an image like as image 1 and stand right next to the image 7. The position of images will be 1-2-3-4-5-6-7-1 and this code can not do it for you.
I suggest you use jquery plugin slider jCarousel Lite .It is simple to use with many awesome configurations and circular
is exactly config which you need. Hope you found this useful. Regards.
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