My git log
is showing something as:
enter code here
[git_trial]$ git log
commit 4c5bc66ae50780cf8dcaf032da98422aea6e2cf7
Author: king <king@king.ap.com>
Date: Thu Jun 30 15:09:55 2011 +0530
This is third commit
commit 8072be67ddd310bc200cab0dccb8bcb2ec4f922c
Author: king <king@king.ap.com>
Date: Thu Jun 30 14:17:27 2011 +0530
This is the second commit
commit 3ba6ce43d500b12f64368b2c27f35211cf189b68
Author: king <king@king.ap.com>
Date: Thu Jun 30 14:00:01 2011 +0530
This is the first git commit for file1
Question 1: Now, how do I check out only my first version?
Question 2: Also, when I do git log
on only File1, why does it show only the first commit?
[git_trial]$ git checkout 3ba6ce43d500b12f64368b2c27f35211cf189b68
Note: moving to "3ba6ce43d500b12f64368b2c27f35211cf189b68" which isn't a local branch
If you want to create a new branch from this checkout, you may do so
(now or later) by using -b with the checkout command again. Example:
git checkout -b <new_branch_name>
[git_trial]$ git log File1
commit 3ba6ce43d500b12f64368b2c27f35211cf189b68
Author: king <king@king.ap.com>
Date: Thu Jun 30 14:00:01 2011 +0530
This is the first git commit for f开发者_Go百科ile1
You can checkout a commit using git checkout sha-of-commit
which you already have.
But you cannot commit anything (as you're not in a branch, you're in a static commit).
If you need to commit anything on top of that commit, you need to check it out into a branch using git checkout sha-of-commit -b testing-a-commit
.
git log <file>
only shows commits that affect that file.
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