I am using an Ajax call to a PHP file to 开发者_如何学Pythonget data from MySQL database and populate select options in HTML. The problem is that duplicate items in the options and I don't know why. I tried the query in workbench and it brings back what I need.
PHP file:
<?php
$q=$_GET["q"];
// open db connection code
$query = "select * from r2rtool.materialtype where type = 'FE' and tools like '%".$q."%'";
$result = mysql_query($query);
$option = "";
while($row = mysql_fetch_array($result))
{
$mat = $row["Material"];
$option.="<option value=\"$mat\">".$mat."</option>";
echo $option;
}
// close db connection
?>
Ajax function:
function populatematerial(str)
{
if (str=="") {
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest) {
// IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else{
// IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200) {
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","phpfile.php?q="+str,true);
xmlhttp.send();
}
while($row = mysql_fetch_assoc($result))
{
$option .= "<option value=\"{$row[Material]}\">{$row[Material]}</option>";
}
echo $option;
All you need to do is to move the echo $option;
out of the while loop, like so:
while($row = mysql_fetch_array($result))
{
$mat = $row["Material"];
$option.="<option value=\"$mat\">".$mat."</option>";
}
echo $option;
You should output the HTML after you built it, not while you build it.
use mysql_fetch_assoc
instead of mysql_fetch_array
because array returns value in numbers and name both format, so it will twice data,
where mysql_fetch_assoc
returns array as only name element of array ..
for more understanding try
<?php
$query = mysql_query("some query ");
$row = mysql_fetch_array($row);
$assoc = mysql_fetch_array($row);
print_r ($row);
echo "<br>";
print_r ($assoc);
echo "<br>";
?>
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