Patterns in Python

This is in python language. I need to print this pattern, depending on the number of lines a user enters:

'##'

'# #'

The next pattern is three spaces away and so on...

This is my code but it prints the second number 开发者_Python百科sign on a different line. I need them to go on the same line.

 def drawPatternIII (lines):
   for i in range(lines):
      for j in range(1):
          print('#')
      for j in range(i+1):
          print (' ', end = '')
      print ('#')

please help!

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You would need to add end="" to the first print() call. While you are at it, remove the pointless for loop with a single iteration.

A concise alternative would be

for i in range(lines):
    print("#" + " "*i + "#")

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The one liner version!

def drawPatternIII (lines):
     list(map(print,["#" + " "*i + "#" for i in range(lines)]))