I'm new to Objective C. I'm trying to use a protocol as I would an interface in Java, but I don't know how or even if it's the right tool for the job. I have defined a protocol in Protocol.h:
@protocol SomeProtocol
- (void)someMethod;
@end
Now, in another class, I need a variable that has someMethod
#import "Protocol.h"
@interface OtherC开发者_C百科lass:NSObject {
SomeProtocol objWithSomeMethod;
}
@end
Of course "SomeProtocol objWithSomeMethod" gives me an error. So is there a way to declare an object that, regardless of type, conforms to this protocol?
Yes, use the angle brackets. You can declare an instance variable to conform to a protocol like this:
id<SomeProtocol> objWithSomeMethod;
If you want it to conform to more than one protocol, you use commas to separate them like this:
id<SomeProtocol, SomeOtherProtocol> objWithSomeMethod;
You can also declare variables or parameters the same way.
Angle brackets qualify objects as implementing protocols. In your example, write
#import "Protocol.h"
@interface OtherClass : NSObject {
id<SomeProtocol> objWithSomeMethod;
}
@end
If you want to declare that a class implements an interface, you use the same notation, essentially:
@interface MyProtocolClass : NSObject <SomeProtocol> {
// ...
}
@end
You should declare your instance variable with his type, then the list of protocols inside <> and finally the variable name. So in your case, it would be:
#import "Protocol.h"
@interface OtherClass:NSObject {
id <SomeProtocol> objWithSomeMethod;
}
@end
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