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Check if the user is typing in numeric numbers. Don't want letters

开发者 https://www.devze.com 2023-03-15 16:55 出处:网络
I would like to know the easiest way to check it the user typing in a letter versus a number. If the user types in a letter it would give them an error message and give them the question back. Right n

I would like to know the easiest way to check it the user typing in a letter versus a number. If the user types in a letter it would give them an error message and give them the question back. Right now I have it so when the user enters a 'q' it will exit the script.

if station == "q":
   开发者_开发知识库     break
else:
        #cursor.execute(u'''INSERT INTO `scan` VALUES(prefix, code_id, answer, %s, timestamp, comport)''',station)
        print 'Thank you for checking into station: ', station

I need it to loop back to the question asking for the station.


Just using python built-in method

str.isdigit()

SEE http://docs.python.org/library/stdtypes.html

e.g.

if station.isdigit():
   print 'Thank you for checking into station: ', station
else:
   # show your error information here
   pass


Try this (using YeJiabin's answer)

def answer():
  station = raw_input("Enter station number: ")
  if not(str.isdigit(station)):
    answer()

Haven't tested that!


With the requirements that you're looking to see if the input string contains anything other than the digits 1..9:

>>> import re
>>> # create a pattern that will match any non-digit or a zero
>>> pat = re.compile(r"[\D0]")
>>> pat.search("12345")
>>> pat.search("123450")
<_sre.SRE_Match object at 0x631fa8>
>>> pat.search("12345A")
<_sre.SRE_Match object at 0x6313d8>
>>> def CheckError(s):
...    if pat.search(s):
...       print "ERROR -- contains at least one bad character."
... 
>>> CheckError("12345")
>>> CheckError("12a")
ERROR -- contains at least one bad character.
>>> CheckError("120")
ERROR -- contains at least one bad character.
>>> 
0

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