What is wrong with my ask.php Syntax?_问答_开发者

开发者 https://www.devze.com 2023-03-15 16:07 出处：网络

So I modified the script as I was instructed earlier, but I am still getting a blank page when I run the HTML form. What is wrong here?

相关专题：php

So I modified the script as I was instructed earlier, but I am still getting a blank page when I run the HTML form. What is wrong here?

UPDATE 2: I get the following error now.

Parse error: syntax error, unexpected T_VARIABLE in /home/content/o/m/o/omorgan/html/dimephysics/adviseme/ask.php on line 32

<?php

ini_set('display_errors',1);
error_reporting(E_ALL|E_STRICT);

//include('config.php');
//include('open_connection.php');



if (!isset($_POST['name']) || !isset($_POST['question']))
    {
        header ("Location: ask.html");
        exit;
    }

    // Database parameters
    $dbhost = '...';
    $dbuser = 'questionme';
    $dbpass = 'Question_2011';
    $dbname = 'questionme';

    $db_name = "questionme";
    $table_name = "questions";

    //Open connection
    $connection = mysql_connect("", "questionme", "Question_2011")
        or die(mysql_error());

    $db = mys开发者_Go百科ql_select_db($db_name, $connection) or die(mysql_error())

    $name = mysql_escape_string($_POST[name]);
    $question = mysql_escape_string($_POST[question]);

    //Insert data into database
    $sql = "INSERT INTO questions
    (name, question) VALUES
    ('$name', '$question')";

?>

<html>
<head>
<title>Ask</title>
<head>
<body>

<h1>Question Submitted</h1>

<p><strong>Name:</strong>
<?php echo $_POST['name']; ?></p>

<p><strong>Question:</strong>
<?php echo $_POST['question']; ?></p>

</body>
</html>

At a bare minimum you need quotes around your array indexes on this line:

if (!isset($_POST[name]) || !isset($_POST[question]))

Make it

if (!isset($_POST['name']) || !isset($_POST['question']))

Also, check your error level (can't give you a link at the moment, in a bit of a rush), PHP should be warning you about this.

try changing

if (!isset($_POST[name]) || !isset($_POST[question]))

if (!isset($_POST['name']) || !isset($_POST['question']))

Place this at the top of the script:

ini_set('display_errors',1);
error_reporting(E_ALL|E_STRICT);

This should let you know whats going on.

Given your error message, it's obvious that your query is failing. You've supressed errors with @ on it, so the or die(...) never kicks in.

Your $table_name in the query is undefined, so the query looks like

INSERT INTO (name, question) ...

which is incorrect SQL.

The two major fixes you need:

Remove the @ supression on mysql_query(). It is almost NEVER acceptable to supress errors, particularly when dealing with a database.
Define $table_name in your script, or change the variable inside the query string to a proper table name.

First of all, don't check with isset. Since $_POST is always generated you should be using !empty().

Remove @'s before mysql_* commands, this makes your script slow and suppresses helpful errors.

And you are having issues because you don't have table variable set, $table_name needs to be defined.

If you are inserting questions to a table named 'questions' simply change your SQL to:

//Insert data into database
$sql = "INSERT INTO `questions` (name, question)
             VALUES ('$name', '$question')";

You forgot add a semicolon *;* in line no. 30

it should be

   $db = mysql_select_db($db_name, $connection) or die(mysql_error());

instead of

  $db = mysql_select_db($db_name, $connection) or die(mysql_error())

You need to end this line:

$db = mysql_select_db($db_name, $connection) or die(mysql_error())

change it to:

$db = mysql_select_db($db_name, $connection) or die(mysql_error());

What is wrong with my ask.php Syntax?

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