I use xdebug php debugger. For example
$date = new DateTime();
var_dump($date);
The output is
object(DateTime)[3]
How to XDebug to show the fields of the object?
current configuration
xdebug.default_enable = 1
xdebug.var_display_max_depth = 5
xdebug.show_local_vars = On
xdebug.show_exception_trace = On
xdebug.dump.SERVER = HTTP_HOST, SERVER_NAME
xdebug开发者_如何学JAVA.dump_globals = Off
xdebug.collect_params = 4
xdebug.show_exception_trace = 1
xdebug.remote_enable = 1
xdebug.remote_host = localhost
xdebug.remote_port = 9000
xdebug.remote_handler = dbgp
xdebug.auto_trace = 1
xdebug.collect_params = 10
var_dump(get_object_vars($date));
var_dump(get_class_methods($date));
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