MYSQL select where column like column1%column2

I have a table with 3 fields, name, firstname and lastname

I want to see how many rows in the table have name of the form firstname%lastname

I tried to do

 select * from family_watchdog_offender where name like firstname%lastname\G

bu开发者_如何学Got that returned a syntax error regarding the %lastname portion of the query. Is there some syntax that will allow me to run a query such as this?

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SELECT * FROM family_watchdog_offender WHERE name  LIKE CONCAT(firstname, '%', lastname);

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Try concat-ing the %:

select * from family_watchdog_offender where name like CONCAT(firstname, '%', lastname)

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I don't think you can do that...This may be what you need to do

SELECT * 
FROM family_watchdog_offender 
WHERE name  LIKE CONCAT(firstname, '%') 
 AND name LIKE CONCAT('%', lastname);