How to implement the function 开发者_JAVA百科?
So it'll output an array containing 2009-12-25 2009-12-26 2009-12-27 2009-12-28 2009-12-29 2009-12-30?
$startdate = strtotime("2009-12-25");
$enddate = strtotime("2009-12-30");
$steps = "1 day";
# Start
$date = $startdate;
while ($date <= $enddate)
{ echo date("Y-m-d", $date)."<br>";
$date = strtotime ("+".$steps, $date); // can be slow with large arrays,
// you can also just add 60*60*24 seconds
// to $date
}
Besides you can use approach similar to the first answer.
$startDate = mktime(0, 0, 0, 12, 25, 2009);
$endDate = mktime(0, 0, 0, 12, 30, 2009);
for ($i=$startDate; $i<=$endDate; $i=$i+86400) {
$timeArray[]=date("Y-m-d", $i);
}
Result:
array (
0 => '2009-12-25',
1 => '2009-12-26',
2 => '2009-12-27',
3 => '2009-12-28',
4 => '2009-12-29',
5 => '2009-12-30',
)
As of php 5.3 you can also use the DatePeriod class.
Use mktime
with an incrementing variable for the day:
$array = array();
for ($x = 25; $x <= 30; $x++) {
$array[] = date('Y-m-d', mktime(0, 0, 0, 12, $x, 2009));
}
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