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How do I flip the orientation of a grid?

开发者 https://www.devze.com 2023-03-15 01:25 出处:网络
I\'m just doing a simple Grid[datasymb开发者_JAVA技巧olgoeshere, Frame->All] command. It\'s taking a list of ID numbers (e.g., {11282,11281,11280}) and placing each one in its own column. I just wa

I'm just doing a simple Grid[datasymb开发者_JAVA技巧olgoeshere, Frame->All] command. It's taking a list of ID numbers (e.g., {11282,11281,11280}) and placing each one in its own column. I just want to flip the orientation so all strings in a single list are placed in the same column (individual rows, one on top of another), and the next list of strings goes in the second column.


Sounds like you want

Grid[Transpose[datasymbolgoeshere],Frame->All]

Edit -- by the way Grid assumes a multidimensional list. It won't complain if you call, eg Grid[{1,2}] but Mma cannot simplify that expression and just returns it as-is. Grid will work with a ragged array, but Transpose will complain, so you will need to pad the elements of datasymbolgoeshere to make your array rectangular.

Putting it all together, something like this should work on most inputs

With[ { maxLength=Length/@data//Max }, PadRight[#,maxLength,""]&/@data//Grid[#,Frame->All]& ]


Rotate[Grid[datasymbolgoeshere, Frame->All],90 Degree]

I like that the contents are still selectable.

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