How in VB.Net can I extract the value from a string using the RegularExpressions class? For example, say I have the string:
[Mon Jan 4 2011] Blah Blah2 Other开发者_运维百科 text
and I want to return the "Mon Jan 4 2011" portion in to a variable. I thought you would use the "Regex.Replace" method but I can't seem to figure out how to extract the portion of the string I want.
In this case, I don't think you need to replace the text, you need to match the text instead.
Regex.Match(input, "(?<=\[)[^\]]+").Value
This takes all the text from right after the first [
up until the next ]
.
Edit: missed a square bracket.
You can use match groups - specifically name the part of the expression you want and reference it by name:
Imports System.Text.RegularExpressions
Module Example
Public Sub Main()
Dim pattern As String = "\[(?<datestring>[^\]]+)\]"
Dim input As String = "[Mon Jan 4 2011] Blah Blah2 Other text"
Dim match As Match = Regex.Match(input, pattern)
' Get the first named group.
Dim group1 As Group = match.Groups.Item("datestring")
Console.WriteLine("Group 'datestring' value: {0}", If(group1.Success, group1.Value, "Empty"))
End Sub
End Module
Try with regex:
\x5B([^\x5D]+)
you can also use this code to achieve your goal:
Dim str As String = "[Mon Jan 4 2011] Blah Blah2 Other text"
Dim m As Match = Regex.Match(str, "\[(?<tag>[^]]*)")
If (m.Success) Then
Debug.Print(m.Result("${tag}")) ' Check "Output Window"
End If
In this code matched result will be stored in named group tag
and will be used accordingly.
i'm suggesting you to follow the article here: http://www.codeproject.com/Articles/9099/The-30-Minute-Regex-Tutorial
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