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SQL Query to Display Values in Table for Logged In User

开发者 https://www.devze.com 2023-03-14 18:52 出处:网络
I am just starting out, very much a rookie and any help would be greatly appreciated.I have a list of URLs in a table called \"url\".I have another table called \"users\" and in that table a column na

I am just starting out, very much a rookie and any help would be greatly appreciated. I have a list of URLs in a table called "url". I have another table called "users" and in that table a column named "username" which list the users of the site. I am looking to display urls for the lo开发者_运维知识库gged in user via a session value of $session->username but have not yet figured out how to only render URLS for the logged in user.

I apologise in advance, I may have the wrong idea but wanted to show you what I was attempting to do but am not able to get to work properly without SQL syntax errors.

$result = $db->query('SELECT * from urls, users INNER JOIN username ON  
$session->username');

Thank you very much


Assuming you have a column named user_id which is making a relation b/w users and urls table. if that column name is named anything else replace the user_id with that column name

$result = $db->query('SELECT * from users u JOIN urls ur 
                      ON  u.username = ur.username 
                      WHERE u.username="'.$session->username.'"');


You need to use the index connection your urls to your user. An user_id for example. This would give you an query like:

$sQuery = "SELECT * FROM users 
INNER JOIN urls ON urls.user_id = users.user_id
WHERE users.username = '".$oSession->username."'";
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