In a bash script, can i use && to group two command line arguments together

Here is a snippet:

for arg in "$@"; do
    if [ $arg == "--coverage" ]; then
        ENABLE_COVERAGE=1
        shift
    elif [ $arg == "--mysql" ]; then
        MYSQL_ONLY=1
        shift
    elif [ $arg == "--psql" ]; then
        PSQL_ONLY=1
        shift
    elif [ $arg == "-h" ] || [ $arg == "--help" ]; then
        usage
        shift
    elif [ $arg == "--qa" ]; then
        QA_ONLY=1
        PSQL_ONLY=1
        MYSQL_ONLY=1
        shift
   elif [ $arg == "--qa" ] && [ $arg == "--mysql" ]; then
        QA_ONLY=1
        MYSQL_ONLY=1
        shift
   elif [ $arg == "--qa" ] && [ $arg == "--psql" ]; then
        QA_ONLY=1
        PSQL_ONLY=1
        shift
    elif [ $arg == "--" ]; then
        shift 
        break          开发者_如何学C                                     
    fi                                                      
done                

---

$arg can never be equal to --qa and --mysql at the same time.

If you're talking about different arguments then yes, you can do something like this:

if [[ $arg1 == "--qa" && $arg2 == "--mysql" ]] ; then
    QA_ONLY=1
    MYSQL_ONLY=1
fi

But I often find it's a better idea to just scan the arguments sequentially setting a flag for each one, then using the flags to decide behaviour. Otherwise you're either limiting your command line arguments to a specific order (xyz --qa --mysql will work but xyz --mysql -- qa won't) or your code becomes hideously complicated since it's trying to check every argument against every possibility.

---

If you can call getopt in bash, you can't call getopt, it shouldn't use long option name. use getopts instead of getopt.(below is a example)

#!/bin/bash

while getopts qm OPT
do
  case $OPT in
    q) opt_qa=1;;
    m) opt_mysql=1;;
  esac
done

if [ $opt_qa = 1 ]; then
  # do as qa
fi

if [ $opt_mysql = 1 ]; then
  # do as mysql
fi