I have the following query:
select col1, sum( col2 ), count( col3 )
from table1
group by col1
order by col1
which returns something like this
col1
dept1
dept2
dept3
col2
10
20
30
col3
2
3
4
Without a stored procedure, is it possible to get a total column be开发者_开发问答low the results generated by the original query?
i.e.
col1
dept1
dept2
dept3
total
col2
10
20
30
60
col3
2
3
4
9
use ROLLUP:
;with Table1 as (
select 'dept1' as col1, 5 as col2,1 as col3
union all
select 'dept1', 5 as col2, 1 as col3
union all
select 'dept2',10,1
union all
select 'dept2',5,1
union all
select 'dept2',5,1
union all
select 'dept3',10,1
union all
select 'dept3',5,1
union all
select 'dept3',5,1
union all
select 'dept3',10,1
)
select COALESCE(col1,'total'), sum( col2 ), count( col3 )
from table1
group by col1
with rollup
order by COALESCE(col1,'ZZZZZ')
Results:
(No column name) (No column name) (No column name)
dept1 10 2
dept2 20 3
dept3 30 4
total 60 9
Have a look at the keyword WITH ROLLUP
on your GROUP BY
clause
yep:
select col1, sum(col2), count(col3)
from table1
group by col1
union all
select 'totals', sum(col2), count(1) from table1
order by col1
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