Python File Search Line And Return Specific Number of Lines after Match

I have a text file that has lines representing some data sets. The file itself is fairly long but it contains certain sections of the following format:

Series_Name                INFO Number of teams : n1
|    Team                                      |     #     |    wins     |
|    TeamName1                                 |     x     |    y        |
.
.
.
|    TeamNamen1                                |     numn  |    numn     |
Some Irrelevant lines
Series_Name2               INFO Number of teams : n1
|    Team                                      |     #     |    wins     |
|    TeamName1                                 |     num1  |    num2     |
.

where each section has a header that begins with the Series_Name. Each Series_Name is different. The line with the header also includes the number of teams in that series, n1. Following the header line is a set of lines that represents a table of data. For each series there are n1+1 rows in the table, where each row shows an individual team name and associated stats. I have been trying to implement a function that will allow the user to search for a Team name and then print out the line in the table associated with that team. However, certain team names show up under multiple series. To resolve this, I am currently trying to write my code so that the user can search for the header line with series name first and then print out just the following n1+1 lines that represent the data associated with the series. Here's what I have come up with so far:

import re
print
fname = raw_input("Enter filename: ")
seriesname = raw_input("Enter series: ")

def findcounter(fname, seriesname):
        logfile = open(fname, "r")

        pat = 'INFO Number of teams :'

        for line in logfile:
                if seriesname in line:
                    if pat in line:
                            s=line

        pattern = re.compile(r"""(?P<name>.*?)     #starting name
                             \s*INFO        #whitespace and success
                             \s*Number\s*of\s*teams  #whitespace and strings
                             \s*\:\s*(?P<n1>.*)""",re.VERBOSE)
        match = pattern.match(s)


        name = match.group("name")
        n1 = int(match.group("n1"))
        print name + " has " + str(n1) + " teams"
        lcount = 0

        for line in logfile:
                if line.startswith(name):
                        if pat in line:
                                while lcount <= n1:
                                        s.append(line)
                                        lcount += 1
                                        return result

The first part of my code works; it matches the header line that the person searches for, parses the line, and then prints ou开发者_如何转开发t how many teams are in that series. Since the header line basically tells me how many lines are in the table, I thought that I could use that information to construct a loop that would continue printing each line until a set counter reached n1. But I've tried running it, and I realize that the way I've set it up so far isn't correct. So here's my question: How do you return a number of lines after a matched line when given the number of desired lines that follow the match? I'm new to programming, and I apologize if this question seems silly. I have been working on this quite diligently with no luck and would appreciate any help.

---

Try something like this instead (slightly pseudocode).

with open('myfile') as fh:
  for line in fh:
    if line == match: # Some actual code here in your conditional:
      for i in range(5):
        additionalData = next(fh)

By calling next(fh) you can retrieve the next line in the file without screwing up your for line in fh loop.