finding numbers that end in 5

I am trying to print out all the numbers from 1 to 100 that end in 5. This is what开发者_JAVA百科 I have:

 for i in range (1, 100):
      if (i/10) == 5:
           print(i)

Why does this print out 50?

---

You want to use modulo % as oppose to division. Modulo gets the remainder.

for i in range (1, 100):
    if (i % 10) == 5:
        print(i)

---

Because 50 / 10 is 5. What you really want is probably this:

for i in range(100):
    if i % 10 == 5:
        print i

% is the modulo operation and gives you the remainder of the integer division of two numbers.

---

Why test the values at all? Just generate the ones you want in the first place.

for i in range(5, 101, 10):
    print (i)

---

This is a great way to become familiar with itertools

From IPython shell:

In [5]: import itertools

In [6]: fives = itertools.count(start=5, step=10)

In [7]: fives.next()
Out[7]: 5

In [8]: fives.next()
Out[8]: 15

In [9]: fives.next()
Out[9]: 25

In [10]: fives.next()
Out[10]: 35

In [11]: fives = itertools.count(start=5, step=10)

In [12]: tmp = itertools.takewhile(lambda x: x <= 100, fives)

In [13]: tmp
Out[13]: <itertools.takewhile at 0x171f65f0>

In [14]: list(tmp)
Out[14]: [5, 15, 25, 35, 45, 55, 65, 75, 85, 95]

It's also a fun history lesson, because list comprehensions and generators in Python have a lot in common with their motivating ancestors from Haskell. Search this page for infinite lists to see what I mean: (link).