HowTo parse numbers from string with BOOST methods?

Problem: Visual C++ 10 project (using MFC and Boost libraries). In one of my methods I'm reading simple test.txt file.

Here is what inside of the file (std::string):

12 asdf789, 54,19 1000 nsfewer:22!13

Then I need to convert all digits to in开发者_Python百科t only with boost methods. For example, I have a list of different characters which I have to parse:

( ’ ' )
( [ ], ( ), { }, ⟨ ⟩ )
( : )
( , )
( ! )
( . )
( - )
( ? )
( ‘ ’, “ ”, « » )
( ; )
( / )

And after conversation I must have some kind of a massive of int's values, like this one:

12,789,54,19,1000,22,13

Maybe some one already did this job?

PS. I'm new for boost.

Thanks!

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Update

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Here is my sample:

std::vector<int> v;

rule<> r = int_p[append(v)] >> *(',' >> int_p[append(v)]);

parse(data.c_str(), r, space_p);

All I have to do, is to add additional escape characters (,'[](){}:!...) in my code, but did not find how to do that!

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• Easy way out is regex.
• Hard way out is using spirit
• Middle-of-the-road is using algorithm::string::split, with the correct separators, and then looping over all individual parts using lexical_cast<>(). That way you can filter out the integers.

But again, regex will be much more robust plus it's much cleaner than all sorts of primitive string manipulation hacking.

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In addition to regex, boost::spirit, and manually parsing the text, you can use AXE parser generator with VC++ 2010. The AXE rule would look something like this (not tested):

std::vector<unsigned> v;
auto text_rule = *(*(axe::r_any() - axe::r_numstr()) & ~axe::r_numstr() 
   >> axe::e_push_back(v)) & axe::r_end();
// test it
std::string str("12 asdf789, 54,19 1000 nsfewer:22!13");
text_rule(str.begin(), str.end());
// print result
std::for_each(v.begin(), v.end(), [](unsigned i) { std::cout << i << '\n'; });

The basic idea it to skip all input characters which don't match the number string rule (r_numstr).