Why C cannot run this program for large array sizes?

When I run this program for large array sizes (e.g. 100000) the following error appears: "General Protection" and the run in halted at line 8 (i.e. c[i]=0;). I wondered if you help me in "How should I modify the following program in order to run"?

#include <stdlib.h>
float *c;
void main()
{开发者_StackOverflow
long i;
c=(float*) malloc (sizeof(float*)*100000);
for (i=0;i<100000;i++)
    c[i]=0;
}

---

Try this:

int main(){ 
  float *c = malloc(sizeof(float) * 100000);
  for (int i=0; i<100000; i++)
    c[i]=0;

  return 0;
}

Edit: I use some C99 features here, and only run for compilers who treats int as 32 bit or 64 bit. This should run with gcc on linux or Mac OS X.

---

This should be:

c=(float*) malloc (sizeof(float)*100000);

---

I think you are using a 16 bit compiler and that malloc can't allocate that much memory in a single contiguous block.

I've just noticed that you are using long as your loop variable rather than the more commonly used int which further backs up my wild guess.

---

float c;

This is a float, not an array. You probably mean:

float *c;

---

c=(float) malloc (sizeof(float*)*100000);

This attempts to cast an array of floats as a float. Again, you probably mean:

c = (float*) malloc (sizeof(float)*100000);