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How do I generate random dark colors in C#?

开发者 https://www.devze.com 2023-03-13 17:15 出处:网络
I generate a random color this way: var random = new Random(); var color = String.Format(\"#{0:X6}\", random.Next(0x1000000));

I generate a random color this way:

 var random = new Random();
 var color = String.Format("#{0:X6}", random.Next(0x1000000)); 
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How can I exclude colors brighter than a certain value?


An quite simple way to get rid of the "upper half" of brightes colors is to mask the result via

random.Next(0x1000000) & 0x7F7F7F


One way to do this is to generate colours in the HSV/HSL colour-space, and then convert to RGB (the Wikipedia article tells you how to do that).

The advantage of HSV is that one of the components (V) corresponds to "brightness". So if you generate H, S and V independently and randomly, but restrict V to low values, then you will get dark colours.


You can install ColorHelper library via NuGet and use next code:

using ColorHelper;
RGB rgb = ColorGenerator.GetDarkRandomColor<RGB>();

Instead of RGB class you can use another. E.g.: HEX, CMYK or another.

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