This is my document:
{
title:"开发者_开发知识库Happy thanksgiving",
body: "come over for dinner",
blocked:[
{user:333, name:'john'},
{user:994, name:'jessica'},
{user:11, name: 'matt'},
]
}
What is the query to find all documents that do not have user 11 in "blocked"?
You can use $in or $nin for "not in"
Example ...
> db.people.find({ crowd : { $nin: ["cool"] }});
I put a bunch more examples here: http://learnmongo.com/posts/being-part-of-the-in-crowd/
Since you are comparing against a single value, your example actually doesn't need a NOT IN operation. This is because Mongo will apply its search criteria to every element of an array subdocument. You can use the NOT EQUALS operator, $ne, to get what you want as it takes the value that cannot turn up in the search:
db.myCollection.find({'blocked.user': {$ne: 11}});
However if you have many things that it cannot equal, that is when you would use the NOT IN operator, which is $nin. It takes an array of values that cannot turn up in the search:
db.myCollection.find({'blocked.user': {$nin: [11, 12, 13]}});
Try the following:
db.stack.find({"blocked.user":{$nin:[11]}})
This worked for me.
See http://docs.mongodb.org/manual/reference/operator/query/nin/#op._S_nin
db.inventory.find( { qty: { $nin: [ 5, 15 ] } } )
This query will select all documents in the inventory collection where the qty field value does not equal 5 nor 15. The selected documents will include those documents that do not contain the qty field.
If the field holds an array, then the $nin operator selects the documents whose field holds an array with no element equal to a value in the specified array (e.g. , , etc.).
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