Hide & show a widget using Jquery

In my form created with symfony 1.4, I have a sfWidgetFormDoctrineChoice in which I choose one of options, I want to hide some field & show them un开发者_StackOverflow社区til my choice was token.

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maybe u should write this code: $('#model_id_table').closest("td").find('label').hide();

*td if your widget is set in table,u can use any other tag.

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Maybe you have problems with widget's name.

So, Visit this Link for more informations : http://api.jquery.com/hide/