Number of lines in all files in a directory [closed]

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I have a folder with many source code files.

I would like to f开发者_如何转开发ind the total number of lines of source code in all files in the directory.

Is there any simple way to do this?

These are cobol files, I do not have a dev tool that will open them, so I cannot just run code metrics.

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Assuming you are using *nix, Mac OS X or even cygwin under Windows:

$ wc -l *

If you want to include subdirectories then you can do it like this:

$ find . -type f -print0 | xargs -0 wc -l

If you just want the grand total (i.e. skip all the individual line counts for each file) then pipe to tail, e.g.

$ find . -type f -print0 | xargs -0 wc -l | tail -1

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use SLOCCOUNT a well-known and free source line of code counting.

It supports COBOL and use COCOMO model to estimate effort and schedule.

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A really quick-n-dirty way to get a close, but not exact, count would be:

tar -c /path/to/source/code | wc -l

This isn't perfectly exact, because tar adds some junk at the beginning, and between each file. If you have any non-ascii files in your source path, that will throw things off, too.