Array
(
[red] => 252
[green] => 168
[blue] => 166
[alpha] => 0
)
It's an output of function imagecolorsforindex.
How can I get a HTML code from these elements? For example: #99CCFFStrictly speaking you can't, since alpha is not supported. But since the alpha is 0, we can assume that it won't matter. As such, pass each value into sprintf()
with a format specifier of %02x
for each element.
c = sprintf('#%02x%02x%02x', val['red'], val['green'], val['blue']);
PHP Convert RGB from/to HTML hex color
rgb2html($array[0], $array[1], $array[2])
There's a function contributed in the comments of this page of the PHP manual.
<?PHP
function rgb2hex2rgb($c){
if(!$c) return false;
$c = trim($c);
$out = false;
if(preg_match("/^[0-9ABCDEFabcdef\#]+$/i", $c)){
$c = str_replace('#','', $c);
$l = strlen($c) == 3 ? 1 : (strlen($c) == 6 ? 2 : false);
if($l){
unset($out);
$out[0] = $out['r'] = $out['red'] = hexdec(substr($c, 0,1*$l));
$out[1] = $out['g'] = $out['green'] = hexdec(substr($c, 1*$l,1*$l));
$out[2] = $out['b'] = $out['blue'] = hexdec(substr($c, 2*$l,1*$l));
}else $out = false;
}elseif (preg_match("/^[0-9]+(,| |.)+[0-9]+(,| |.)+[0-9]+$/i", $c)){
$spr = str_replace(array(',',' ','.'), ':', $c);
$e = explode(":", $spr);
if(count($e) != 3) return false;
$out = '#';
for($i = 0; $i<3; $i++)
$e[$i] = dechex(($e[$i] <= 0)?0:(($e[$i] >= 255)?255:$e[$i]));
for($i = 0; $i<3; $i++)
$out .= ((strlen($e[$i]) < 2)?'0':'').$e[$i];
$out = strtoupper($out);
}else $out = false;
return $out;
}
?>
Output
#FFFFFF =>
Array{
red=>255,
green=>255,
blue=>255,
r=>255,
g=>255,
b=>255,
0=>255,
1=>255,
2=>255
}
#FFCCEE =>
Array{
red=>255,
green=>204,
blue=>238,
r=>255,
g=>204,
b=>238,
0=>255,
1=>204,
2=>238
}
CC22FF =>
Array{
red=>204,
green=>34,
blue=>255,
r=>204,
g=>34,
b=>255,
0=>204,
1=>34,
2=>255
}
0 65 255 => #0041FF
255.150.3 => #FF9603
100,100,250 => #6464FA
You can try this simple piece of code below.
$rgb = (123,222,132);
$rgbarr = explode(",",$rgb,3);
echo sprintf("#%02x%02x%02x", $rgbarr[0], $rgbarr[1], $rgbarr[2]);
This will return #7bde84
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