In Selenium 2 I want to ensure that an element on the page that the driver has loaded does not exist. I'm including my naive implementation here.
WebElement deleteLink = null;
try {
deleteLink = driver.findElement(By.className("commentEdit"开发者_如何学运维));
} catch (NoSuchElementException e) {
}
assertTrue(deleteLink != null);
Is there a more elegant way that basically verifies to assert that NoSuchElementException was thrown?
If you are testing using junit and that is the only thing you are testing you could make the test expect an exception using
@Test (expected=NoSuchElementException.class)
public void someTest() {
driver.findElement(By.className("commentEdit"));
}
Or you could use the findElements
method that returns an list of elements or an empty list if none are found (does not throw NoSuchElementException
):
...
List<WebElement> deleteLinks = driver.findElements(By.className("commentEdit"));
assertTrue(deleteLinks.isEmpty());
...
or
....
assertTrue(driver.findElements(By.className("commentEdit")).isEmpty());
....
You can use this:
Boolean exist = driver.findElements(By.whatever(whatever)).size() == 0;
If it doesn't exist will return true.
I split out page classes so I don't have to define elements more than once. My nunit and mbunit test classes call those page classes. I haven't tried this out yet but this is how I'm thinking about doing it so I can use .exists() like I did with WatiN.
Extension Class:
public static class ExtensionMethods
{
public static IWebElement ElementById(this IWebDriver driver, string id)
{
IWebElement e = null;
try
{
e = driver.FindElement(By.Id(id));
}
catch (NoSuchElement){}
return e;
}
public static bool Exists(this IWebElement e)
{
if (e == null)
return false;
return true;
}
}
Page Class:
public IWebElement SaveButton { get { try { return driver.ElementById("ctl00_m_m_body_body_cp2_btnSave")); } }
Test Class:
MyPageClass myPageClass = new MyPageClass(driver);
if (myPageClass.SaveButton.Exists())
{
Console.WriteLine("element doesn't exist");
}
You can retrieve a list of elements by using driver.findElements("Your elements") and then search for the element. if the list doesn't contains the element you got yourself your desired behavior :)
If you're using the Javascript API, you can use WebElement.findElements()
. This method will return a Promise with an array of found elements. You can check the length of the array to ensure no items were found.
driver.findElements(By.css('.selector')).then(function(elements) {
expect(elements.length).to.equal(0)
})
I'm using Chai assertion library inside the Promise's callback to expect a certain value.
Reference: https://seleniumhq.github.io/selenium/docs/api/javascript/module/selenium-webdriver/index_exports_WebElement.html
Best solution
protected boolean isElementPresent(WebElement el){
try{
el.isDisplayed();
return true;
}
catch(NoSuchElementException e){
return false;
}
}
public boolean exist(WebElement el){
try {
el.isDisplayed();
return true;
}catch (NoSuchElementException e){
return false;
}
}
if(exist(By.id("Locator details"))==false)
or
WebElement el= driver.findElementby(By.locator("locator details")
public boolean exists(WebElement el)
try{
if (el!=null){
if (el.isDisplayed()){
return true;
}
}
}catch (NoSuchElementException e){
return false;
}
}
Using webdriver find_element_xxx()
will raise exception in my code and take us the waiting time of implicit/explicit webdriver wait.
I will go for DOM element check
webdriver.execute_script("return document.querySelector('your css class')")
p.s.
Also found similar discussion on our QA-main sister site here
For full check for visibility+existence
# check NOT visible the :aftermeet and :viewintro
# ! . . ! !offsetWidth to check visible in pure js ref. https://stackoverflow.com/a/20281623/248616
css='yourcss'; e=wd.execute_script(f"return document.querySelector('{css}').offsetWidth > 0") ; assert not e
# check NOT exists :viewintro
css='yourcss'; e=wd.execute_script(f"return document.querySelector('{css}')") ; assert not e
Use assertFalse :)
assertFalse(isElementPresent(By.className("commentEdit")));
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