I have an XML like this:
<!--...-->
<Cell X="4" Y="2" CellType="Magnet">
<Direction>180</Direction>
<SwitchOn>true</SwitchOn>
<Color>-65536</Color>
</Cell>
<!--...-->
There're many Cell elements
, and I can get the Cell Nodes by GetElementsByTagName
. However, I realise that Node
class DOESN'T have GetElementsByTagName
method! How c开发者_JAVA技巧an I get Direction
node from that cell node, without go throught the list of ChildNodes
? Can I get the NodeList
by Tag name like from Document
class?
Thank you.
You can cast the NodeList
item again with Element
and then use getElementsByTagName();
from Element
class.
The best approach is to make a Cell Object
in your project alongwith fields like Direction
, Switch
, Color
. Then get your data something like this.
String direction [];
NodeList cell = document.getElementsByTagName("Cell");
int length = cell.getLength();
direction = new String [length];
for (int i = 0; i < length; i++)
{
Element element = (Element) cell.item(i);
NodeList direction = element.getElementsByTagName("Direction");
Element line = (Element) direction.item(0);
direction [i] = getCharacterDataFromElement(line);
// remaining elements e.g Switch , Color if needed
}
Where your getCharacterDataFromElement()
will be as follow.
public static String getCharacterDataFromElement(Element e)
{
Node child = e.getFirstChild();
if (child instanceof CharacterData)
{
CharacterData cd = (CharacterData) child;
return cd.getData();
}
return "";
}
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