Is `id` a keyword in python?

My editor (TextMate) shows id in another colour (when used as vari开发者_C百科able name) than my usual variable names. Is it a keyword? I don't want to shade any keyword...

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id is not a keyword in Python, but it is the name of a built-in function.

The keywords are:

and       del       from      not       while
as        elif      global    or        with
assert    else      if        pass      yield
break     except    import    print
class     exec      in        raise
continue  finally   is        return
def       for       lambda    try

Keywords are invalid variable names. The following would be a syntax error:

if = 1

On the other hand, built-in functions like id or type or str can be shadowed:

str = "hello"    # don't do this

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You can also get help from python:

>>> help(id)
Help on built-in function id in module __builtin__:

id(...)
    id(object) -> integer

    Return the identity of an object.  This is guaranteed to be unique among
    simultaneously existing objects.  (Hint: it's the object's memory address.)

or alternatively you can question IPython

IPython 0.10.2   [on Py 2.6.6]
[C:/]|1> id??
Type:           builtin_function_or_method
Base Class:     <type 'builtin_function_or_method'>
String Form:    <built-in function id>
Namespace:      Python builtin
Docstring [source file open failed]:
    id(object) -> integer

Return the identity of an object.  This is guaranteed to be unique among
simultaneously existing objects.  (Hint: it's the object's memory address.)

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Just for reference purposes:

Check if something is a keyword in Python:

>>> import keyword  
>>> keyword.iskeyword('id')
False

Check all the keywords in Python:

>>> keyword.kwlist
['and', 'as', 'assert', 'break', 'class', 'continue', 'def', 'del', 'elif',
 'else', 'except', 'exec', 'finally', 'for', 'from', 'global', 'if', 'import',
 'in', 'is', 'lambda', 'not', 'or', 'pass', 'print', 'raise', 'return', 'try',
 'while', 'with', 'yield']

---

It's a built in function:

id(...)
    id(object) -> integer

    Return the identity of an object.  This is guaranteed to be unique among
    simultaneously existing objects.  (Hint: it's the object's memory address.)