I'm working on a program that works with functions like x + 3
. The pr开发者_如何转开发ogram is able to calculate the equation and give the user a table of values. What I want to do next is to add the option to enter something like x + a
. If the user puts the x
value at 1
, for instance, I want it to be able to say 1 + a
. What I believe that I need in order to do this is to separate the string into an array, and then have it detect any characters that are alphabet (aside from x
). I already know how to separate the string, but is there a way to detect an alphabet character without having to do something like a huge case switch?
Compare each character to the end points of the alphabet.
char c = ...; if( ( c >= 'a' && c <='z' ) || ( c >='A' && c <= 'Z' ) ) it's a character;
(I don't know the objective C syntax)
(I'm so bad at formatting on this site it's not even funny)
Instead of splitting the string manually, you could use a NSScanner to examine the string components.
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